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► Planning an IFR flight from Paris to London for the twin jet aeroplane. Given:
Estimated Landing Mass: 49.700 kg
Cruising level: FL280
W/V: 280°/40kt
Average True Course: 320°
Procedure for descent: M.74/250 KIAS
Determine the distance from the top of descent to London (Elevation 80ft)
Answer: 76 NM
1) Find the Time and Air distance from table
Enter the table from the left with 28.000ft and from the top with 49.700kg
As those 2 values are not given, we need to use interpolation
Interpolate between 27.000ft and 29.000ft
Interpolate between 45.000kg and 55.000kg
Air distance = 86 NAM
Time = 19min
2) Find TAS
V = D / T
V = 86NM / 19min (19/60)
V = 272kt
3) Find Groundspeed
Wind direction (280) - True course (320) = -40
COS(-40) = 0.77 (Positive value so HWC)
0.77 x windspeed (40) = 31 HWC
727 TAS - 31 HWC = 241 GS
4) Find Distance with groundspeed
D = V x T
D = 241 x 19min
D = 76NM
► Planning an IFR flight from Paris (Charles de Gaulle) to London (Heathrow) for a twin jet aeroplane. Given:
Estimated takeoff mass (TOM): 52.000 kg
Airport elevation: 387 ft
FL280
W/V: 280°/40kt
ISA Deviation: -10°C
Average true course: 340°
Find the time to the top of climb (TOC).
A) 12 min
B) 3 min
C) 11 min
D) 15 min
Enter table from the left with 28.000ft and from the top with 52.000kg:
Time = 11 min
► Planning an IFR flight from Paris to London for a twin jet aeroplane. Given:
Estimated takeoff mass (TOM): 52.000 kg
Airport elevation: 387 ft
FL280
W/V: 280°/40kt
ISA Deviation: -10°C
Average true course: 340°
Find ground distance to the top of climb (TOC).
A) 53 NM
B) 56 NM
C) 50 NM
D) 47 NM
If we enter the table with 28.000ft and 52.000kg we find:
Time = 11 minutes
Distance = 53 NM (AIR DISTANCE!)
We need to convert it to GROUND DISTANCE and for that we need TAS & GS:
V = D (53) / T (11min)
V = 289kt
Find the wind approx component via formula (or wind scale):
Wind direction (280) - Course (340) = -60
COS(-60) = 0.5 (positive value so HWC)
0.5 x wind speed (40) = 20kt HWC
289 TAS - 20 = 269 GS
NGM = (NAM / TAS) x GS
NGM = (53 / 289) x 269
NGM = 50
(or you can use D = T (11min) x V(269) )
► Planning an IFR flight from Paris to London for the twin jet aeroplane. Given:
Estimated takeoff mass (TOM): 52.000 kg
Airport elevation: 387 ft
Cruise: FL280
W/V: 280°/40kt
ISA Deviation: -10°C
Average true course: 340°
Find fuel to the top of climb (TOC).
A) 1.100 kg
B) 1.000 lbs
C) 1.000 kg
D) 1.500 lbs
Enter the table from the left with 28.000ft and from the top with 52.000kg and find the fuel needed to be 1000 (units can be found in the top left box of the table).
Estimated Landing Mass: 49.700 kg
Cruising level: FL280
W/V: 280°/40kt
Average True Course: 320°
Procedure for descent: M.74/250 KIAS
Determine the distance from the top of descent to London (Elevation 80ft)
Answer: 76 NM
1) Find the Time and Air distance from table
Enter the table from the left with 28.000ft and from the top with 49.700kg
As those 2 values are not given, we need to use interpolation
Interpolate between 27.000ft and 29.000ft
Interpolate between 45.000kg and 55.000kg
Air distance = 86 NAM
Time = 19min
2) Find TAS
V = D / T
V = 86NM / 19min (19/60)
V = 272kt
3) Find Groundspeed
Wind direction (280) - True course (320) = -40
COS(-40) = 0.77 (Positive value so HWC)
0.77 x windspeed (40) = 31 HWC
727 TAS - 31 HWC = 241 GS
4) Find Distance with groundspeed
D = V x T
D = 241 x 19min
D = 76NM
► Planning an IFR flight from Paris (Charles de Gaulle) to London (Heathrow) for a twin jet aeroplane. Given:
Estimated takeoff mass (TOM): 52.000 kg
Airport elevation: 387 ft
FL280
W/V: 280°/40kt
ISA Deviation: -10°C
Average true course: 340°
Find the time to the top of climb (TOC).
A) 12 min
B) 3 min
C) 11 min
D) 15 min
Enter table from the left with 28.000ft and from the top with 52.000kg:
Time = 11 min
► Planning an IFR flight from Paris to London for a twin jet aeroplane. Given:
Estimated takeoff mass (TOM): 52.000 kg
Airport elevation: 387 ft
FL280
W/V: 280°/40kt
ISA Deviation: -10°C
Average true course: 340°
Find ground distance to the top of climb (TOC).
A) 53 NM
B) 56 NM
C) 50 NM
D) 47 NM
If we enter the table with 28.000ft and 52.000kg we find:
Time = 11 minutes
Distance = 53 NM (AIR DISTANCE!)
We need to convert it to GROUND DISTANCE and for that we need TAS & GS:
V = D (53) / T (11min)
V = 289kt
Find the wind approx component via formula (or wind scale):
Wind direction (280) - Course (340) = -60
COS(-60) = 0.5 (positive value so HWC)
0.5 x wind speed (40) = 20kt HWC
289 TAS - 20 = 269 GS
NGM = (NAM / TAS) x GS
NGM = (53 / 289) x 269
NGM = 50
(or you can use D = T (11min) x V(269) )
► Planning an IFR flight from Paris to London for the twin jet aeroplane. Given:
Estimated takeoff mass (TOM): 52.000 kg
Airport elevation: 387 ft
Cruise: FL280
W/V: 280°/40kt
ISA Deviation: -10°C
Average true course: 340°
Find fuel to the top of climb (TOC).
A) 1.100 kg
B) 1.000 lbs
C) 1.000 kg
D) 1.500 lbs
Enter the table from the left with 28.000ft and from the top with 52.000kg and find the fuel needed to be 1000 (units can be found in the top left box of the table).
