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► You have to cover an air distance of 2.000 NM. What will be your flight time given the following information?
Takeoff Mass: 150.000 kg
Planned Cruise: Long Range Mach at FL350
Conditions: Standard Atmosphere (ISA)
CG: 37%
A) 359 minutes
B) 303 minutes
C) 288 minutes
D) 298 minutes
1 - Enter the integrated cruise table with 150.000kg
It gives us 2464 NAM and 359 minutes
We have to cover 2000 NAM so: 2464 - 2000 = 464 NAM
Now find the closest value to 464 in the table = 472 NAM and 73 minutes
359 minutes - 73 minutes = 286 minutes
2 - Now we need to add the climb and descent corrections (2 other tables provided)
From the climb correction annex we find 6 minutes
From the descent correction annex we find 10 minutes
286 + 10 + 6 = 302 minutes
► A turbojet aeroplane flies using the following data:
Flight level: FL 330
Flight regime: "long range" (LR)
Mass: 156.500 kg
Tailwind component at this level: 40 kt
With a remaining flight time of 1h 10min the ground distance that can be covered by the aeroplane at cruising speed is:
A) 539 NM
B) 471 NM
C) 493 NM
D) 18 NM
Takeoff Mass: 150.000 kg
Planned Cruise: Long Range Mach at FL350
Conditions: Standard Atmosphere (ISA)
CG: 37%
A) 359 minutes
B) 303 minutes
C) 288 minutes
D) 298 minutes
1 - Enter the integrated cruise table with 150.000kg
It gives us 2464 NAM and 359 minutes
We have to cover 2000 NAM so: 2464 - 2000 = 464 NAM
Now find the closest value to 464 in the table = 472 NAM and 73 minutes
359 minutes - 73 minutes = 286 minutes
2 - Now we need to add the climb and descent corrections (2 other tables provided)
From the climb correction annex we find 6 minutes
From the descent correction annex we find 10 minutes
286 + 10 + 6 = 302 minutes
► A turbojet aeroplane flies using the following data:
Flight level: FL 330
Flight regime: "long range" (LR)
Mass: 156.500 kg
Tailwind component at this level: 40 kt
With a remaining flight time of 1h 10min the ground distance that can be covered by the aeroplane at cruising speed is:
A) 539 NM
B) 471 NM
C) 493 NM
D) 18 NM
